Producing 135 ml of a fragrance oil
For more on this project see these web pages: And these videos:
I have a formula for a new fragrance. The formula is written in percentages of the weights of each aroma material measured in grams. One milliliter of the formula weights 0.98 grams (see video). The formula for this fragrance appears below:
Formula for a new fragrance
Note: The names of the aroma materials shown above are coded and refer to specific materials from specific vendors. Additionally, some of these materials are dillutions of the material and neither the percentage of dillution nor the solvent used are shown here.
One milliliter of the formula weighs 0.98 grams. To produce 135 ml I'll need 132.3 grams of the formula.
Now, using my percentages, I can calculate the weight in grams I'll need of each of the twelve aroma materials.
Starting with "G", I multiply 132.3 (the total weight in grams needed) times 6.110 (the percentage of the formula, by weight that "G" represents) and divide the result by 100 (since 6.100 is a percent!) and the result shows me that I'll need 8.096 grams of "G".
132.3 x 6.110 / 100 = 8.096
When I do my calculations for my other eleven aroma materials I come out with these results:
Calculated production weights in grams
Using an electronic spreadsheet makes the calculations easy, particularly when you have a large number of aroma materials.
Now, with the weights in hand, I'm ready to get out my electronic balance and produce 132.5 grams of the formula, which will yield the 135 ml I need to produce the finished perfume.
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